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2) How many different 13-card bridge hands contain a singleton in hearts and two five-card suits? [A5 marks](A singleton is exactly one card of a particular suit. A five-card suit is exactly five cards of the same suit.)

Question

  1. How many different 13-card bridge hands contain a singleton in hearts and two five-card suits? [A5 marks](A singleton is exactly one card of a particular suit. A five-card suit is exactly five cards of the same suit.)
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Solution

To solve this problem, we need to break it down into several steps:

  1. First, we need to choose which suit will be the singleton. Since we know it's hearts, this step is already done for us.

  2. Next, we need to choose which card in the hearts suit will be the singleton. There are 13 cards in a suit, so there are 13 choices for this step.

  3. Then, we need to choose which two suits will be the five-card suits. There are 3 remaining suits (spades, diamonds, clubs), and we need to choose 2 of them. This can be done in 3 ways.

  4. For each of the two five-card suits, we need to choose which 5 cards will be in the suit. There are 13 cards in a suit, and we need to choose 5 of them. This can be done in "13 choose 5" ways, or 1287 ways. Since we need to do this twice (once for each suit), the total number of ways is 1287 * 1287 = 1,656,769.

  5. Finally, we need to choose the remaining 2 cards from the remaining suit. There are 13 cards left in this suit, and we need to choose 2 of them. This can be done in "13 choose 2" ways, or 78 ways.

Multiplying all these together, we get the total number of different 13-card bridge hands that meet the criteria:

13 (singleton choices) * 3 (suit choices) * 1,656,769 (five-card suit choices) * 78 (remaining card choices) = 390,564,894,834 different hands.

This problem has been solved

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