The expansion of (x + y)⁶ using the binomial theorem is:

(x + y)⁶ = C(6, 0)x⁶y⁰ + C(6, 1)x⁵y¹ + C(6, 2)x⁴y² + C(6, 3)x³y³ + C(6, 4)x²y⁴ + C(6, 5)x¹y⁵ + C(6, 6)x⁰y⁶

Where C(n, r) is the binomial coefficient, which can be calculated as:

C(n, r) = n! / [r!(n - r)!]

So, the expansion becomes:

(x + y)⁶ = x⁶ + 6x⁵y + 15x⁴y² + 20x³y³ + 15x²y⁴ + 6xy⁵ + y⁶

Question

The expansion of (x + y)⁶ using the binomial theorem is:

(x + y)⁶ = C(6, 0)x⁶y⁰ + C(6, 1)x⁵y¹ + C(6, 2)x⁴y² + C(6, 3)x³y³ + C(6, 4)x²y⁴ + C(6, 5)x¹y⁵ + C(6, 6)x⁰y⁶

Where C(n, r) is the binomial coefficient, which can be calculated as:

C(n, r) = n! / [r!(n - r)!]

So, the expansion becomes:

(x + y)⁶ = x⁶ + 6x⁵y + 15x⁴y² + 20x³y³ + 15x²y⁴ + 6xy⁵ + y⁶

Knowee AI · Accepted Answer

The expansion of (x + y)⁶ using the binomial theorem is:

(x + y)⁶ = C(6, 0)x⁶y⁰ + C(6, 1)x⁵y¹ + C(6, 2)x⁴y² + C(6, 3)x³y³ + C(6, 4)x²y⁴ + C(6, 5)x¹y⁵ + C(6, 6)x⁰y⁶

Where C(n, r) is the binomial coefficient, which can be calculated as:

C(n, r) = n! / [r!(n - r)!]

So, the expansion becomes:

(x + y)⁶ = x⁶ + 6x⁵y + 15x⁴y² + 20x³y³ + 15x²y⁴ + 6xy⁵ + y⁶

Find the expansion of (𝑥 + 𝑦)6