If a = 4.36, b = 2.39, c = 1.97, then the value of a3-b3-c3-3abc is
Question
If a = 4.36, b = 2.39, c = 1.97, then the value of a3-b3-c3-3abc is
Solution
The given expression is a^3 - b^3 - c^3 - 3abc.
Step 1: Substitute the given values into the expression.
= (4.36)^3 - (2.39)^3 - (1.97)^3 - 3*(4.36)(2.39)(1.97)
Step 2: Calculate the cube of each number.
= 83.14496 - 13.654619 - 7.661933 - 3*(4.36)(2.39)(1.97)
Step 3: Multiply the numbers in the last term.
= 83.14496 - 13.654619 - 7.661933 - 3*20.54268
Step 4: Multiply the last term.
= 83.14496 - 13.654619 - 7.661933 - 61.62804
Step 5: Subtract the numbers.
= -0.799632
So, the value of a^3 - b^3 - c^3 - 3abc when a = 4.36, b = 2.39, c = 1.97 is approximately -0.80.
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