What is normal force acting on each bolt (ϒTex)in corner connection 5 bolts are arranged in one row connecting gusset plate with thickness 10 mm and two angles 80*8, with e = 3 cm and P = 10 cm, using M20 grade 8.8 bolts. Steel used is steel 52. Cat.A, N=7 t (Factored load)?a.3.6tb.4.4tc.6.2 td.1.4t

To answer this question, we need to understand the concept of normal force and how it applies to bolts in a connection.

Normal force is the force that a surface exerts on an object that is pressing against it. In this case, the normal force is the force that the gusset plate and the angles exert on the bolts.

The normal force on each bolt can be calculated by dividing the total force by the number of bolts. However, in this case, we are not given the total force. Instead, we are given the factored load (N=7 t), which is the load that the connection is designed to withstand, taking into account various factors such as the material properties and safety factors.

The grade of the bolts (8.8) tells us about the bolt's strength. The first number (8) indicates the tensile strength of the bolt, and the second number (.8) indicates the yield strength.

The size of the bolt (M20) tells us the diameter of the bolt.

The thickness of the gusset plate and the size of the angles (80*8) tell us about the geometry of the connection.

The distances e and P are the edge distance and the pitch, respectively, which are used to determine the layout of the bolts.

Given all this information, we can calculate the normal force on each bolt. However, without knowing the total force acting on the connection, we cannot provide a numerical answer.

Please provide the total force acting on the connection so that we can calculate the normal force on each bolt.