If P(2,3,1) is a point and L=x−y−a−2=0 is a plane then
Question
If P(2,3,1) is a point and L=x−y−a−2=0 is a plane then
Solution
To solve this problem, we need to find the relationship between the given point P(2,3,1) and the plane L=x−y−a−2=0.
Step 1: Substitute the coordinates of the point P(2,3,1) into the equation of the plane L=x−y−a−2=0.
L(2,3,1) = 2−3−a−2 = -1−a
Step 2: Set the expression obtained in step 1 equal to zero, since the equation of the plane is L=x−y−a−2=0.
-1−a = 0
Step 3: Solve the equation for 'a'.
-1−a = 0 a = -1
Therefore, the value of 'a' that satisfies the equation of the plane L=x−y−a−2=0 and the given point P(2,3,1) is a = -1.
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