A particle moves according to the equation; x = 10t2,where x is in meters and t is in seconds. Find the velocity forthe time interval from 2.0 s to 2.1 s

particle starts moving rectilinearly at time t=0 such that its velocity v changes with time t according to equation v=t2−t where t is in seconds and v in ms−1. Find the time interval for which the particle retards.0.5s < t < 1 s0.5s < t < 2 s0.5s < t < 3 s0.5s < t < 5 s

The velocity time graph of a particle moving along a straight time as shown in figure. Calculate the displacement covered between t = 0 to t = 10 seconds.

A particle moves rectilinearly with a constant acceleration 1 m/s2. Its speed after 10 seconds is 5 m/s. The distance covered by the particle in this duration is (Initial & final velocities are in opposite direction)

The position of a particle is defined by the equation s = 0.12t3 + 0.9t2 - 4t + 6, where s is in metres and t is in seconds. This equation is valid for the time range t=0 to t=5 seconds. Determine the following:(a) the velocity of the particle at t=1 second, v = Answer m/s(b) the acceleration of the particle at t=1 second, a = Answer m/s2

The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.a(t) = 2t + 2,    v(0) = −15,    0 ≤ t ≤ 5(a) Find the velocity at time t.v(t) = m/s(b) Find the distance traveled during the given time interval.