Figure shows variation of internal energy (U) with the pressure (P) of 2.0 moles gas in cyclic process abcda. The temperature of gas at c and d are 300 K and 500 K. Heat absorbed in the process is 400 R ln X. Find the value of X.
Question
Figure shows variation of internal energy (U) with the pressure (P) of 2.0 moles gas in cyclic process abcda. The temperature of gas at c and d are 300 K and 500 K. Heat absorbed in the process is 400 R ln X. Find the value of X.
Solution
To find the value of X, we need to use the given information about the heat absorbed in the process. The heat absorbed is given as 400 R ln X.
First, let's understand the meaning of the term "ln X". ln X represents the natural logarithm of X.
Next, we can substitute the given values into the equation. The heat absorbed is 400 R ln X.
Now, we need to determine the value of X. To do this, we can rearrange the equation to solve for X.
Dividing both sides of the equation by 400 R, we get ln X = (heat absorbed) / (400 R).
To isolate X, we can take the exponential of both sides of the equation. This cancels out the natural logarithm, leaving us with X = e^((heat absorbed) / (400 R)).
Therefore, the value of X is e^((heat absorbed) / (400 R)).
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