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Select the correct answerWhat will be the output of the following Java program?import java.lang.System;  class Output   {    public static void main(String args[])    {      byte a[] = { 65, 66, 67, 68, 69, 70 };      byte b[] = { 71, 72, 73, 74, 75, 76 };        System.arraycopy(a, 0, b, 3, a.length - 3);      System.out.print(new String(a) + " " + new String(b));    }  }OptionsOPQRST UVWXYZOPQRST OPQRSTOPQRST UVWOPQUVWOPQ UVWOPQ

Question

Select the correct answerWhat will be the output of the following Java program?import java.lang.System;  class Output   {    public static void main(String args[])    {      byte a[] = { 65, 66, 67, 68, 69, 70 };      byte b[] = { 71, 72, 73, 74, 75, 76 };        System.arraycopy(a, 0, b, 3, a.length - 3);      System.out.print(new String(a) + " " + new String(b));    }  }OptionsOPQRST UVWXYZOPQRST OPQRSTOPQRST UVWOPQUVWOPQ UVWOPQ

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Solution

The correct answer is "OPQRST UVWOPQ".

Here's the step by step explanation:

  1. The byte arrays a and b are initialized with ASCII values ranging from 65 to 76. When these values are converted to characters, a becomes "OPQRST" and b becomes "UVWXYZ".

  2. The System.arraycopy method is called with a as the source array, 0 as the source position, b as the destination array, 3 as the destination position, and a.length - 3 as the length. This means that the last three elements of a ("OPQ") are copied into b, starting at the fourth position.

  3. The System.out.print statement prints the new strings formed from a and b, separated by a space. Since a has not been modified, it still prints as "OPQRST". However, b has been modified to "UVWOPQ" due to the array copy operation.

So, the output of the program is "OPQRST UVWOPQ".

This problem has been solved

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