A can do a piece of work in 8 days and B can do the same work in 10 days. They started the work together but after 3 days, A left . In how many days B can complete the remaining work?
Question
A can do a piece of work in 8 days and B can do the same work in 10 days. They started the work together but after 3 days, A left . In how many days B can complete the remaining work?
Solution
First, let's find out how much work A and B can do in a day.
A can finish the work in 8 days, so A can do 1/8 of the work in a day. B can finish the work in 10 days, so B can do 1/10 of the work in a day.
When they work together, they can do (1/8 + 1/10) of the work in a day. This simplifies to 9/40 of the work in a day.
They worked together for 3 days, so in 3 days, they did 3 * (9/40) = 27/40 of the work.
This means that the remaining work is 1 - 27/40 = 13/40 of the work.
Now, B is left to do the remaining work alone. Since B can do 1/10 of the work in a day, it will take B (13/40) / (1/10) = 13/4 = 3.25 days to finish the remaining work.
So, B can complete the remaining work in 3.25 days.
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