Statement-I : Water is a better proton donor than alcohol, this suggest hydroxide is stronger base than alkoxide.Statement-II : Electron releasing group increase electron density on oxygen in alcohol, tending to decrease the polarity of O–H bond.A Statement-I and II both are correct. B Statement-I is correct but statement-II is false. C Statement-I is incorrect but statement-II is correct. D Both statement-I and II are incorrect.
Question
Statement-I : Water is a better proton donor than alcohol, this suggest hydroxide is stronger base than alkoxide.Statement-II : Electron releasing group increase electron density on oxygen in alcohol, tending to decrease the polarity of O–H bond.A Statement-I and II both are correct. B Statement-I is correct but statement-II is false. C Statement-I is incorrect but statement-II is correct. D Both statement-I and II are incorrect.
Solution
Statement-I: Water is a better proton donor than alcohol, suggesting hydroxide is a stronger base than alkoxide.
Statement-II: Electron-releasing groups increase electron density on oxygen in alcohol, tending to decrease the polarity of the O-H bond.
To determine the correctness of these statements, we need to evaluate each statement individually.
Statement-I: Water is a better proton donor than alcohol, suggesting hydroxide is a stronger base than alkoxide.
This statement is correct. Water has a higher tendency to donate protons (H+) compared to alcohol. Hydroxide (OH-) is the conjugate base of water and is a stronger base than alkoxide, which is the conjugate base of alcohol.
Statement-II: Electron-releasing groups increase electron density on oxygen in alcohol, tending to decrease the polarity of the O-H bond.
This statement is also correct. Electron-releasing groups, such as alkyl groups, donate electron density to the oxygen atom in alcohol. This donation of electron density decreases the polarity of the O-H bond, making it less acidic.
Therefore, both Statement-I and Statement-II are correct.
The correct answer is option A: Statement-I and II both are correct.
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