A technician is working in an environmental research laboratory. She has 1000 soil samples and 982 of them do not contain hazardous material.The technician randomly picks a soil sample. Let the event A and the event B be as follows.A: The sample the technician picks does not contain hazardous material.B: The sample the technician picks contains hazardous material.Find the following probabilities. Write your answers as decimal numbers and do not round.

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Solution 1

The question seems to be incomplete. Could you please provide the specific probabilities you want to find?

Solution 2

The question seems to be incomplete. Could you please provide the specific probabilities that need to be found?

Solution 3

The question seems to be incomplete as it does not specify which probabilities need to be found. However, I can provide the probabilities of events A and B.

Probability of event A (P(A)): The event A is that the sample the technician picks does not contain hazardous material. There are 982 samples that do not contain hazardous material out of a total of 1000 samples. So, the probability of event A is calculated as follows:

P(A) = Number of favorable outcomes / Total number of outcomes P(A) = 982 / 1000 = 0.982
Probability of event B (P(B)): The event B is that the sample the technician picks contains hazardous material. There are 1000 total samples and 982 of them do not contain hazardous material, so 18 of them do contain hazardous material. The probability of event B is calculated as follows:

P(B) = Number of favorable outcomes / Total number of outcomes P(B) = 18 / 1000 = 0.018

Please provide more details if you need other probabilities.

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