Determine the mass (in g) of nitric acid (HNO3) in 60.00 cm3 of a 3.00 mol dm–3 solution.
Question
Determine the mass (in g) of nitric acid (HNO3) in 60.00 cm3 of a 3.00 mol dm–3 solution.
Solution
Sure, here are the steps to determine the mass of nitric acid in the solution:
Step 1: Convert the volume from cm3 to dm3. We know that 1 dm3 = 1000 cm3. So, 60.00 cm3 = 60.00/1000 = 0.0600 dm3.
Step 2: Use the formula for molarity which is moles/volume. We know the molarity (3.00 mol dm–3) and the volume (0.0600 dm3), so we can find the moles of HNO3.
Moles = Molarity x Volume = 3.00 mol dm–3 x 0.0600 dm3 = 0.18 mol.
Step 3: Convert moles to grams. We know that the molar mass of HNO3 is approximately 63.01 g/mol.
Mass = Moles x Molar mass = 0.18 mol x 63.01 g/mol = 11.34 g.
So, the mass of nitric acid in the solution is approximately 11.34 grams.
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