python code :let the product of three distinct number be X now if x is given find those three distinct numbers such that their sum is maximum

The problem you're asking is not well-defined because there are infinite possibilities of three distinct numbers that can multiply to give a product X. However, if we assume that the numbers are positive integers, we can use a simple approach to find three numbers whose product is X and whose sum is maximum.

Here is a Python code that does this:

def find_numbers(X):
    # Initialize the numbers as 1
    numbers = [1, 1, X]

    # Iterate until the product is no longer a perfect cube
    while X % numbers[2] == 0 and numbers[2] != 1:
        # Divide the product by the current number
        X //= numbers[2]

        # Update the numbers
        numbers[0] *= numbers[2]
        numbers[1] *= numbers[2]
        numbers[2] = X

    # Return the numbers
    return numbers

# Test the function
X = 100
print(find_numbers(X))

This code works by initially setting the three numbers to 1, 1, and X. It then repeatedly divides X by the current number until X is no longer a perfect cube. The numbers are then updated by multiplying them by the current number. This process is repeated until the product is no longer a perfect cube. The resulting three numbers are then returned.

Please note that this code assumes that X is a perfect cube of a positive integer. If X is not a perfect cube, the code will not work correctly. Also, this code does not guarantee that the sum of the three numbers is maximum, as the problem is not well-defined.