Each of the four bars shown in (Figure 2) can rotate freely in the horizontal plane about its left end. For which diagrams is the net torque equal to zero?Select all that apply.ABCD

A 3.0-m rod is pivoted about its left end. A force of 20 N is applied perpendicular to the rod at a distance of1.2 m from the pivot causing a ccw torque, and a force of 4.8 N is applied at the end of the rod 3.0 m from the pivot. The 4.8-N force is at an angle of 30o to the rod and causes a cw torque. What is the net torque about the pivot? (Take ccw as positive.)Select one:a.-16.8 N·mb.31.2 N·mc.-31.2 N·md.16.8 N·me.​9.6 N·m

What is the value of the net torque produced by the forces at B and C?

Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 7.00 cm and b = 19.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.) N · mA wheel rotating about an axle is approximated as two concentric circles with the center defined to be O. The radius of the inner circle is a and the radius of the outer circle is b. Three arrows representing individual forces are as follows.An arrow labeled 12.0 N acts on the top left of the inner circle, and points down and to the left at an angle of 30.0° below the horizontal.An arrow labeled 10.0 N acts on the top of the outer circle and points to the right.An arrow labeled 9.00 N acts on the right of the outer circle and points down.

torque acting clockwise is taken as

Write the necessary equations of equilibrium of the object shown in the figure below. Take the origin of the torque equation about an axis perpendicular to the page through the point O. (Let counterclockwise torque be positive and let forces to the right and up be positive. Use the following as necessary: the forces Rx, Ry, Fx, Fy, and Fg; the length ℓ of the object; and the angle 𝜃 that the object makes with the horizontal.)A rod of length ℓ makes an acute angle 𝜃 clockwise from the horizontal. A point at the left end of the rod is labeled O. Five forces act on the rod as follows.A force with magnitude Rx begins at the left end of the rod and points horizontally left.A force with magnitude Ry begins at the left end of the rod and points vertically up.A force vector Fg begins at the center of the rod and points vertically down.A force with magnitude Fx begins at the right end of the rod and points horizontally right.A force with magnitude Fy begins at the right end of the rod and points vertically up.ΣFx = = 0ΣFy = = 0Σ𝜏 = 0 = 0