What is the output of the second println statement in the main method? public class Foo { int i; static int s; public static void main(String[] args) { Foo f1 = new Foo(); System.out.println("f1.i is " + f1.i + " f1.s is " + f1.s); Foo f2 = new Foo(); System.out.println("f2.i is " + f2.i + " f2.s is " + f2.s); Foo f3 = new Foo(); System.out.println("f3.i is " + f3.i + " f3.s is " + f3.s); } public Foo() { i++; s++; } } Group of answer choicesf2.i is 1 f2.s is 1f2.i is 1 f2.s is 2f2.i is 2 f2.s is 2f2.i is 2 f2.s is 1
Question
What is the output of the second println statement in the main method? public class Foo { int i; static int s; public static void main(String[] args) { Foo f1 = new Foo(); System.out.println("f1.i is " + f1.i + " f1.s is " + f1.s); Foo f2 = new Foo(); System.out.println("f2.i is " + f2.i + " f2.s is " + f2.s); Foo f3 = new Foo(); System.out.println("f3.i is " + f3.i + " f3.s is " + f3.s); } public Foo() { i++; s++; } } Group of answer choicesf2.i is 1 f2.s is 1f2.i is 1 f2.s is 2f2.i is 2 f2.s is 2f2.i is 2 f2.s is 1
Solution 1
The output of the second println statement in the main method would be "f2.i is 1 f2.s is 2".
Here's why:
In the Foo class, there are two variables: 'i' (an instance variable) and 's' (a static variable).
When we create a new instance of Foo (f1), both 'i' and 's' are incremented by 1 in the constructor. So, for f1, 'i' is 1 and 's' is also 1.
When we create the second instance of Foo (f2), 'i' is again set to 0 (because it's a new instance) and then incremented by 1 in the constructor. So, for f2, 'i' is 1. However, 's' is a static variable, which means it's shared among all instances of the class. Since it was already incremented once when f1 was created, it starts at 1 for f2 and then is incremented again in the constructor. So, for f2, 's' is 2.
Therefore, the output of the second println statement is "f2.i is 1 f2.s is 2".
Solution 2
The output of the second println statement in the main method would be "f2.i is 1 f2.s is 2".
Here's why:
In the Foo class, there are two variables: 'i' and 's'. 'i' is an instance variable and 's' is a static variable.
When we create an object of the Foo class (like f1, f2, f3), each object gets its own copy of the instance variable 'i'. However, all objects share the same copy of the static variable 's'.
In the constructor of the Foo class, both 'i' and 's' are incremented by 1.
So, when the first object (f1) is created, 'i' and 's' are both incremented by 1. Therefore, the output of the first println statement is "f1.i is 1 f1.s is 1".
When the second object (f2) is created, 'i' is again incremented by 1 (because f2 has its own copy of 'i'), but 's' is incremented by 1 again (because all objects share the same copy of 's'). Therefore, the output of the second println statement is "f2.i is 1 f2.s is 2".
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