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At a pizza shop, 70% of the customers order a pizza, 25% of the customers order a salad, and 15% of the customers order both a pizza and a salad.If a customer is chosen at random, what is the probability that he or she orders either a pizza or a salad?A.0.45B.0.95C.0.80D.0.175

Question

At a pizza shop, 70% of the customers order a pizza, 25% of the customers order a salad, and 15% of the customers order both a pizza and a salad.If a customer is chosen at random, what is the probability that he or she orders either a pizza or a salad?A.0.45B.0.95C.0.80D.0.175

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Solution

The probability of a customer ordering either a pizza or a salad can be found by adding the probability of ordering a pizza to the probability of ordering a salad and then subtracting the probability of ordering both (since we're double counting those in the first two probabilities).

The probability of ordering a pizza is 0.70, the probability of ordering a salad is 0.25, and the probability of ordering both is 0.15.

So, the probability of ordering either a pizza or a salad is 0.70 + 0.25 - 0.15 = 0.80.

Therefore, the answer is C. 0.80.

This problem has been solved

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