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ssume host X's window size is 6 and segments 5001 through 5006 have alreadybeen sent. Host X then receives an ACK with ACK sequence number set to 5003.Segments 5007 through 5011 are waiting to be transmitted by host X.

Question

ssume host X's window size is 6 and segments 5001 through 5006 have alreadybeen sent. Host X then receives an ACK with ACK sequence number set to 5003.Segments 5007 through 5011 are waiting to be transmitted by host X.

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Solution

Based on the given information, let's analyze the scenario step by step:

  1. Host X's window size is 6, which means it can have up to 6 unacknowledged segments in flight at a time.

  2. Segments 5001 through 5006 have already been sent by Host X. This means that these segments are currently in transit and have not yet been acknowledged by the receiver.

  3. Host X receives an ACK with an ACK sequence number set to 5003. This indicates that the receiver has successfully received and acknowledged segment 5003.

  4. Segments 5007 through 5011 are waiting to be transmitted by Host X. Since the window size is 6 and segment 5003 has been acknowledged, Host X can now transmit segments 5007 through 5012 (up to the window size limit).

In summary, Host X can now transmit segments 5007 through 5012, as segment 5003 has been acknowledged by the receiver.

This problem has been solved

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