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A metallic sphere of mass 2.2 kg and volume  2.5×10−4m3 is completely immersed in water. What is the buoyant force exerted by water on the sphere. Density of water is  1000kg/m3

Question

A metallic sphere of mass 2.2 kg and volume  2.5×10−4m3 is completely immersed in water. What is the buoyant force exerted by water on the sphere. Density of water is  1000kg/m3

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Solution

To find the buoyant force, we can use Archimedes' principle which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.

Step 1: Calculate the volume of the water displaced by the sphere. Since the sphere is completely immersed in water, the volume of the water displaced is equal to the volume of the sphere, which is 2.5×10^-4 m^3.

Step 2: Calculate the mass of the water displaced. We can use the formula for mass which is density times volume. The density of water is given as 1000 kg/m^3. So, the mass of the water displaced is 1000 kg/m^3 * 2.5×10^-4 m^3 = 0.25 kg.

Step 3: Calculate the weight of the water displaced. Weight is mass times gravity. Assuming the acceleration due to gravity is 9.8 m/s^2, the weight of the water displaced is 0.25 kg * 9.8 m/s^2 = 2.45 N.

Therefore, the buoyant force exerted by the water on the sphere is 2.45 N.

This problem has been solved

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