3(2c + d) – d ; c = 5, d = −1
Question
3(2c + d) – d ; c = 5, d = −1
Solution
Sure, let's solve the equation step by step:
First, substitute the values of c and d into the equation. So, c = 5 and d = -1.
The equation becomes: 3(2*5 + -1) - -1
Simplify the equation inside the parentheses first (according to the order of operations, or BIDMAS/BODMAS/PEDMAS): 3(10 - 1) + 1
Which simplifies to: 3(9) + 1
Then, multiply: 27 + 1
Finally, add to get the result: 28
Similar Questions
5c3 – 6c2 – 2c ; c = −5
Solve for d.9 + 2 + d = –d − 1
What value of d is a solution to this equation?–3–2d=–3d–9d=–6d=7Submit
Use the quadratic formula to solve. Express your answer in simplest form.4, d, squared, minus, 5, d, minus, 5, equals, 3, d4d 2 −5d−5=3d
Find the product. Write your solution in standard form. (3c−5)(c+3)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.