How many numbers of three digits can be formed with digits 1, 3, 5, 7 and 9?*2 points9831203455430

To solve this problem, we need to understand that we are forming a three-digit number using the digits 1, 3, 5, 7, and 9. This means that for each place in the three-digit number, we have 5 options (the digits 1, 3, 5, 7, and 9).

Step 1: Consider the hundreds place. We can choose any of the 5 digits to place here. So, we have 5 options.

Step 2: Next, consider the tens place. Since we have already used one digit in the hundreds place, we are left with 4 digits. So, we have 4 options for this place.

Step 3: Finally, consider the units place. We have already used two digits in the hundreds and tens places, so we are left with 3 digits. So, we have 3 options for this place.

Step 4: Since each place is independent of the others, we multiply the number of options together to get the total number of three-digit numbers we can form. So, the total number of three-digit numbers is 5 * 4 * 3 = 60.

So, 60 three-digit numbers can be formed with the digits 1, 3, 5, 7, and 9.