If a number 774958A96B is divisible by 8 and 9, the respectively values of A and B will be

To find the values of A and B, we need to consider the rules of divisibility for 8 and 9.

1. A number is divisible by 8 if the last three digits of the number form a number that is divisible by 8. In this case, the last three digits are A96. Since 896 (when A=8) is divisible by 8, A must be 8.

2. A number is divisible by 9 if the sum of its digits is divisible by 9. If we add up the known digits (7+7+4+9+5+8+9+6=55) and add A (which we found to be 8), we get 63. To make the total divisible by 9, B must be 0, because 63 is already divisible by 9.

So, A is 8 and B is 0.