Ramanuj walked from “Tower A” to “Tower B” in the East 10 feet. Then she turned to the right and walked 3 feet. Again he turned to the right and walked 14 feet. How far is she from Tower A?
Question
Ramanuj walked from “Tower A” to “Tower B” in the East 10 feet. Then she turned to the right and walked 3 feet. Again he turned to the right and walked 14 feet. How far is she from Tower A?
Solution
Ramanuj initially walked 10 feet east from Tower A to Tower B. Then, he turned right and walked 3 feet. This means he is now 3 feet south of Tower B. When he turned right again and walked 14 feet, he moved westward. Since he initially moved 10 feet east, moving 14 feet west means he is now 4 feet west of Tower A.
To find the total distance from Tower A, we need to calculate the hypotenuse of the right triangle formed by the 3 feet south and 4 feet west distances. We can use the Pythagorean theorem for this, which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.
So, the calculation would be as follows:
Square of distance south = 3^2 = 9 Square of distance west = 4^2 = 16
Adding these together gives 25. The square root of 25 is 5.
So, Ramanuj is 5 feet away from Tower A.
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