To answer this question, we need to use Snell's Law, which states that the ratio of the sine of the angles of incidence and refraction is equivalent to the ratio of velocities of light in the two media, or the inverse of the refractive indices.

Mathematically, this is expressed as:

sin(i) / sin(r) = v1 / v2

where:
i = angle of incidence
r = angle of refraction
v1 = propagation velocity in Medium 1
v2 = propagation velocity in Medium 2

Given:
i = 30°
v1 = 1200 m/s
v2 = 1300 m/s

We can substitute these values into Snell's Law:

sin(30) / sin(r) = 1200 / 1300

Solving for sin(r) gives us:

sin(r) = sin(30) * (1300 / 1200)

This gives us a value for sin(r) that is greater than sin(30), which means that the angle of refraction r is greater than the angle of incidence i.

Therefore, the refracted angle is away from the normal.

Question

To answer this question, we need to use Snell's Law, which states that the ratio of the sine of the angles of incidence and refraction is equivalent to the ratio of velocities of light in the two media, or the inverse of the refractive indices.

Mathematically, this is expressed as:

sin(i) / sin(r) = v1 / v2

where:
i = angle of incidence
r = angle of refraction
v1 = propagation velocity in Medium 1
v2 = propagation velocity in Medium 2

Given:
i = 30°
v1 = 1200 m/s
v2 = 1300 m/s

We can substitute these values into Snell's Law:

sin(30) / sin(r) = 1200 / 1300

Solving for sin(r) gives us:

sin(r) = sin(30) * (1300 / 1200)

This gives us a value for sin(r) that is greater than sin(30), which means that the angle of refraction r is greater than the angle of incidence i.

Therefore, the refracted angle is away from the normal.

Knowee AI · Accepted Answer

To answer this question, we need to use Snell's Law, which states that the ratio of the sine of the angles of incidence and refraction is equivalent to the ratio of velocities of light in the two media, or the inverse of the refractive indices.

Mathematically, this is expressed as:

sin(i) / sin(r) = v1 / v2

where:
i = angle of incidence
r = angle of refraction
v1 = propagation velocity in Medium 1
v2 = propagation velocity in Medium 2

Given:
i = 30°
v1 = 1200 m/s
v2 = 1300 m/s

We can substitute these values into Snell's Law:

sin(30) / sin(r) = 1200 / 1300

Solving for sin(r) gives us:

sin(r) = sin(30) * (1300 / 1200)

This gives us a value for sin(r) that is greater than sin(30), which means that the angle of refraction r is greater than the angle of incidence i.

Therefore, the refracted angle is away from the normal.

Suppose that the propagation velocity of Medium 2 is 1300 m / sec and the propagation velocity of Medium 1 is 1200 m / sec. For an incident angle is 30°, is the refracted angle toward or away from normal? toward no refraction occurs away from

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