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What is the recursive formula for this geometric sequence?–4, –24, –144, –864, ...A.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙4{ a 1​ =−6a n​ =a n−1​ ∙4​ B.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙6{ a 1​ =−4a n​ =a n−1​ ∙6​ C.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−4a n​ =a n−1​ ∙30​ D.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−6a n​ =a n−1​ ∙30​

Question

What is the recursive formula for this geometric sequence?–4, –24, –144, –864, ...A.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙4{ a 1​ =−6a n​ =a n−1​ ∙4​ B.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙6{ a 1​ =−4a n​ =a n−1​ ∙6​ C.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−4a n​ =a n−1​ ∙30​ D.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−6a n​ =a n−1​ ∙30​

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Solution

The recursive formula for a geometric sequence is given by a_n = a_n-1 * r, where r is the common ratio.

To find the common ratio, we divide any term by the previous term.

For example, -24 / -4 = 6, -144 / -24 = 6, -864 / -144 = 6.

So, the common ratio (r) is 6.

The first term (a_1) of the sequence is -4.

Therefore, the recursive formula for this geometric sequence is {a_1 = -4, a_n = a_n-1 * 6}.

So, the correct answer is B. {a_1 = -4, a_n = a_n-1 * 6}.

This problem has been solved

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