A student dissolves 14.g of phenol C6H5OH in 425.mL of a solvent with a density of 1.08/gmL. The student notices that the volume of the solvent does not change when the phenol dissolves in it.Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

To calculate the molarity and molality of the solution, we first need to find the number of moles of phenol and the volume of the solution in liters.

1. Calculate the number of moles of phenol:

The molar mass of phenol (C6H5OH) is approximately 94.11 g/mol.

Number of moles = mass / molar mass Number of moles = 14 g / 94.11 g/mol = 0.149 mol (rounded to three decimal places for significant figures)

2. Calculate the volume of the solution in liters:

We know that the volume of the solvent does not change when the phenol dissolves in it. So, the volume of the solution is the same as the volume of the solvent.

Volume = 425 mL = 0.425 L (since 1 L = 1000 mL)

3. Calculate the molarity:

Molarity (M) = moles of solute / volume of solution in liters Molarity = 0.149 mol / 0.425 L = 0.351 M (rounded to three decimal places for significant figures)

4. Calculate the molality:

First, we need to find the mass of the solvent in kg. We know that the density of the solvent is 1.08 g/mL, so:

Mass of solvent = volume of solvent x density of solvent Mass of solvent = 425 mL x 1.08 g/mL = 459 g = 0.459 kg (since 1 kg = 1000 g)

Molality (m) = moles of solute / mass of solvent in kg Molality = 0.149 mol / 0.459 kg = 0.325 m (rounded to three decimal places for significant figures)

So, the molarity of the solution is 0.351 M and the molality of the solution is 0.325 m.