What is the electric potential energy of a system that consists of two protons 2.4×10−15 mm apart-as might occur inside a typical nucleus?
Question
What is the electric potential energy of a system that consists of two protons 2.4×10−15 mm apart-as might occur inside a typical nucleus?
Solution
The electric potential energy (U) of a system of two charges can be calculated using the formula:
U = k * q1 * q2 / r
where:
- k is Coulomb's constant (8.99 * 10^9 N m^2/C^2),
- q1 and q2 are the charges (for a proton, the charge is 1.6 * 10^-19 C), and
- r is the distance between the charges.
Given that the distance is 2.4 * 10^-15 m (note that the distance should be in meters, not millimeters), we can substitute these values into the formula:
U = (8.99 * 10^9 N m^2/C^2) * (1.6 * 10^-19 C)^2 / (2.4 * 10^-15 m)
Solving this equation will give the electric potential energy of the system in Joules.
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