To solve this problem, we can use the physics formula for the final velocity of an object in free fall, which is given by:

v = sqrt(2gh)

where:
- v is the final velocity (which we're trying to find)
- g is the acceleration due to gravity (given as 10 m/s²)
- h is the height from which the object is dropped (given as 2 m)

Substituting the given values into the formula, we get:

v = sqrt(2 * 10 m/s² * 2 m) = sqrt(40 m²/s²) = 6.3 m/s

So, the speed of the stone when it hits the floor is 6.3 m/s. The correct answer is e. 6.3 m/s.

Question

To solve this problem, we can use the physics formula for the final velocity of an object in free fall, which is given by:

v = sqrt(2gh)

where:
- v is the final velocity (which we're trying to find)
- g is the acceleration due to gravity (given as 10 m/s²)
- h is the height from which the object is dropped (given as 2 m)

Substituting the given values into the formula, we get:

v = sqrt(2 * 10 m/s² * 2 m) = sqrt(40 m²/s²) = 6.3 m/s

So, the speed of the stone when it hits the floor is 6.3 m/s. The correct answer is e. 6.3 m/s.

Knowee AI · Accepted Answer

To solve this problem, we can use the physics formula for the final velocity of an object in free fall, which is given by:

v = sqrt(2gh)

where:
- v is the final velocity (which we're trying to find)
- g is the acceleration due to gravity (given as 10 m/s²)
- h is the height from which the object is dropped (given as 2 m)

Substituting the given values into the formula, we get:

v = sqrt(2 * 10 m/s² * 2 m) = sqrt(40 m²/s²) = 6.3 m/s

So, the speed of the stone when it hits the floor is 6.3 m/s. The correct answer is e. 6.3 m/s.

A 5 kg stone is dropped from a height of 2 m. What is the speed of the stone when it hits the floor? Consider g = 10 ms-2Question 2Select one:a.10 m/sb.12.6 m/sc.5 m/sd.2 m/se.6.3 m/s

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