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In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:21 m26 m28 m29 mNone

Question

In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:21 m26 m28 m29 mNone

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Solution

Let's break down the problem:

  1. In a 100 m race, A beats B by 25 m. This means when A runs 100 m, B runs only 75 m.

  2. In the same 100 m race, B beats C by 4 m. This means when B runs 100 m, C runs only 96 m.

  3. Now, we need to find out how much A can beat C. For this, we need to find out how much C runs when A runs 100 m.

  4. From step 1, we know that when A runs 100 m, B runs 75 m. So, when B runs 75 m, C would run 96/100 * 75 = 72 m (because when B runs 100 m, C runs 96 m).

  5. Therefore, when A runs 100 m, C runs 72 m.

  6. So, A beats C by 100 - 72 = 28 m.

So, the answer is 28 m.

This problem has been solved

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