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Suppose the wait to pass through immigration at JFK Airport in New York is thought to be bell-shaped and symmetrical with a mean of 19 minutes. It is known that 68% of travelers will spend between 5 and 33 minutes waiting to pass through immigration. The standard deviation for the wait time through immigration is _________.Multiple Choice18 minutes17 minutes14 minutes16 minutes

Question

Suppose the wait to pass through immigration at JFK Airport in New York is thought to be bell-shaped and symmetrical with a mean of 19 minutes. It is known that 68% of travelers will spend between 5 and 33 minutes waiting to pass through immigration. The standard deviation for the wait time through immigration is _________.Multiple Choice18 minutes17 minutes14 minutes16 minutes

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Solution

The standard deviation for a normal distribution (bell-shaped and symmetrical) is calculated by subtracting the lower limit from the upper limit and then dividing by 2 times the z-score for the given percentage.

In this case, the lower limit is 5 minutes, the upper limit is 33 minutes, and the z-score for 68% is approximately 1 (more precisely, it's 0.9945, but in most cases, we use 1 for simplicity).

So, the standard deviation is (33 - 5) / (2 * 1) = 14 minutes.

Therefore, the standard deviation for the wait time through immigration is 14 minutes.

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