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If both parents are heterozygous for an autosomal dominant condition, what is the probability of an offspring inheriting the disease? You might like to draw a Punnet square to help work out the answer.Group of answer choices25%75%50%0%

Question

If both parents are heterozygous for an autosomal dominant condition, what is the probability of an offspring inheriting the disease? You might like to draw a Punnet square to help work out the answer.Group of answer choices25%75%50%0%

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Solution

To answer this question, we can use a Punnett square, which is a simple graphical way of discovering all of the potential combinations of genotypes that can occur in children, given the parents' genotypes.

Here's how we can do it:

  1. Since both parents are heterozygous for the condition, their genotypes are both Aa (where A represents the dominant allele and a represents the recessive allele).

  2. We set up a Punnett square with each parent's genotype along one side. This gives us a 2x2 grid.

  3. We then fill in the squares by combining the alleles from each parent. This gives us the following combinations: AA, Aa, aA, and aa.

  4. Since the condition is autosomal dominant, an individual only needs one copy of the dominant allele to have the condition. Therefore, the genotypes AA, Aa, and aA would all result in the condition.

  5. So, out of the four possible outcomes, three of them result in the condition. This means that the probability of an offspring inheriting the disease is 75%.

This problem has been solved

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