Assume that d is a Python dictionary. What does the following Python code produce?result = dict()for key in d: val = d[key] if val not in result: result[val] = [key] else: result[val].append(key)Question 3Select one:a.a histogramb.an inverted dictionaryc.a list of tuplesd.a lookupe.a reverse lookup
Question
Assume that d is a Python dictionary. What does the following Python code produce?result = dict()for key in d: val = d[key] if val not in result: result[val] = [key] else: result[val].append(key)Question 3Select one:a.a histogramb.an inverted dictionaryc.a list of tuplesd.a lookupe.a reverse lookup
Solution
The given Python code produces an inverted dictionary.
Here's a step-by-step explanation:
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An empty dictionary named 'result' is created.
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The code then iterates over each key in the dictionary 'd'.
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For each key, it gets the corresponding value 'val' from the dictionary 'd'.
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It then checks if this value 'val' is already a key in the 'result' dictionary.
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If 'val' is not a key in 'result', it creates a new key-value pair in 'result' with 'val' as the key and the original key from 'd' as the value (in a list).
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If 'val' is already a key in 'result', it appends the original key from 'd' to the list of values for 'val' in 'result'.
So, the 'result' dictionary is an inverted version of 'd', where the values in 'd' become keys in 'result' and the keys in 'd' become values in 'result'. Therefore, the correct answer is (b) an inverted dictionary.
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