[1 - cos(nπ/2) - sin(nπ/2)]^2Z transform of it

What is the z-transform of the signal x(n)=sin(jω0n)u(n)?a) z−1sinω01+2z−1cosω0+z−2b) z−1sinω01−2z−1cosω0−z−2c) z−1cosω01−2z−1cosω0+z−2d) z−1sinω01−2z−1cosω0+z−2

Z transform of it

By the integration by parts, we haveZ π−πf (x) cos(nx)dx = 1n f (x) sin(nx)π−π− 1nZ π−πf (x) sin(nx)dx

Find the Z-transform of 𝒏𝒄𝒐𝒔(𝒏 𝜽)

What is the z-transform of the signal x(n)=[3(2n)−4(3n)]u(n)𝑥(𝑛)=[3(2𝑛)−4(3𝑛)]𝑢(𝑛) ?Select one:a.3(1+2z−1)−4(1+3z−1)3(1+2𝑧−1)−4(1+3𝑧−1)b.3(1−2z−1)−4(1−3z−1)3(1−2𝑧−1)−4(1−3𝑧−1)c.3(1−2z)−4(1−3z)3(1−2𝑧)−4(1−3𝑧)d.None of the options