Knowee
Questions
Features
Study Tools

Question 5The chef at a pizza restaurant tosses a spinning disk of pizza dough into the air. As the disk stretches outward in midair and its diameter increases, what happens to the disk's angular momentum and angular velocity about the disk's center of mass? [Note that the disk's weight, which acts at the disk's center of gravity, produces zero torque on the disk about the disk's center of mass. Ignore any effects due to the air.]1 pointThe disk's angular velocity is constant, but the disk's angular momentum increases.The disk's angular momentum is constant, but the disk's angular velocity increases.The disk's angular momentum is constant, but the disk's angular velocity decreases.The disk's angular momentum and angular velocity are both constant.

Question

Question 5The chef at a pizza restaurant tosses a spinning disk of pizza dough into the air. As the disk stretches outward in midair and its diameter increases, what happens to the disk's angular momentum and angular velocity about the disk's center of mass? [Note that the disk's weight, which acts at the disk's center of gravity, produces zero torque on the disk about the disk's center of mass. Ignore any effects due to the air.]1 pointThe disk's angular velocity is constant, but the disk's angular momentum increases.The disk's angular momentum is constant, but the disk's angular velocity increases.The disk's angular momentum is constant, but the disk's angular velocity decreases.The disk's angular momentum and angular velocity are both constant.

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The correct answer is "The disk's angular momentum is constant, but the disk's angular velocity decreases."

Here's why:

Angular momentum (L) is the product of the moment of inertia (I) and the angular velocity (ω). It can be represented by the equation L = Iω.

When the chef tosses the spinning disk of pizza dough into the air, the dough stretches and its diameter increases. This means the moment of inertia (I) of the dough increases because the mass of the dough is now distributed further from the center of mass.

According to the law of conservation of angular momentum, the total angular momentum of a system remains constant unless acted on by an external torque. In this case, we're told to ignore any effects due to the air and that the disk's weight produces zero torque. This means there's no external torque acting on the dough, so its angular momentum remains constant.

However, because the moment of inertia (I) has increased and the angular momentum (L) is constant, the angular velocity (ω) must decrease to maintain the equation L = Iω.

So, as the disk of pizza dough stretches outward in midair and its diameter increases, its angular momentum remains constant, but its angular velocity decreases.

This problem has been solved

Similar Questions

What is the rotational inertia of a solid iron disk of mass 41.0 kg with a thickness of 5.00 cm and radius of 30.0 cm, about an axis perpendicular to the disk and passing through its center?

A uniform disk with mass 41.0 kgkg and radius 0.220 mm is pivoted at its center about a horizontal, frictionless axle that is stationary. The disk is initially at rest, and then a constant force 29.5 NN is applied tangent to the rim of the disk.Part AWhat is the magnitude v𝑣 of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.190 revolution?Express your answer with the appropriate units.Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typev𝑣 =ratnothing

Mass per unit area of a circular disc of radius a depends on the distance r from its centre as σ(r) = A + BrThe moment of inertia of the disc about the the axis, perpendicular to the plane and passing through its centre is :

As shown in the figure, a uniform disc of mass m and radius r rolls along a horizontal surface and then moves up along a curved inclined surface. If the disc has a linear velocity v on the horizontal surface, and expression for moment of inertia of the disc is 𝑚𝑟2 2 , what is the maximum height the disc (its center) will travel up (Consider the possibility of the disc having a rotational kinetic energy = 1/2Iω2)? A) 𝑣2 2𝑔 B) 3𝑣2 2𝑔 C) 3𝑣2 4𝑔 D) 𝑣2 𝑔 E) 2𝑣2 g

A wooden disk with a moment of inertia of 5 kg m2 rotates with an angular speed of 50 rad/s. A metal cylinder with rotational inertia 20 kg m2 is dropped from rest onto the wooden cylinder so that their centers coincide.(a) When the cylinders no longer slip against each other, what is the final angular speed of the rotating system?

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.