The perimeter of a rectangle is given by the formula 2*(length + width).

For the given rectangle, the perimeter is 2*(60 yards + 100 yards) = 320 yards.

If we want another rectangle with the same perimeter but a larger area, we need to adjust the length and width such that the product of the length and width (which gives the area) is maximized.

The maximum area of a rectangle given a fixed perimeter is achieved when the rectangle is a square. This is because for a fixed perimeter, the area of a rectangle (length*width) is maximized when length = width.

So, to maximize the area, we should set the length and width to be equal.

Therefore, the length and width of the rectangle should each be half of the perimeter, which is 320 yards / 2 = 160 yards.

So, the length and width of the rectangle that has the same perimeter but a larger area are both 160 yards.

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The perimeter of a rectangle is given by the formula 2*(length + width).

For the given rectangle, the perimeter is 2*(60 yards + 100 yards) = 320 yards.

If we want another rectangle with the same perimeter but a larger area, we need to adjust the length and width such that the product of the length and width (which gives the area) is maximized.

The maximum area of a rectangle given a fixed perimeter is achieved when the rectangle is a square. This is because for a fixed perimeter, the area of a rectangle (length*width) is maximized when length = width.

So, to maximize the area, we should set the length and width to be equal.

Therefore, the length and width of the rectangle should each be half of the perimeter, which is 320 yards / 2 = 160 yards.

So, the length and width of the rectangle that has the same perimeter but a larger area are both 160 yards.

Knowee AI · Accepted Answer

The perimeter of a rectangle is given by the formula 2*(length + width).

For the given rectangle, the perimeter is 2*(60 yards + 100 yards) = 320 yards.

If we want another rectangle with the same perimeter but a larger area, we need to adjust the length and width such that the product of the length and width (which gives the area) is maximized.

The maximum area of a rectangle given a fixed perimeter is achieved when the rectangle is a square. This is because for a fixed perimeter, the area of a rectangle (length*width) is maximized when length = width.

So, to maximize the area, we should set the length and width to be equal.

Therefore, the length and width of the rectangle should each be half of the perimeter, which is 320 yards / 2 = 160 yards.

So, the length and width of the rectangle that has the same perimeter but a larger area are both 160 yards.

A rectangular field is 60 yards wide and 100 yards long.Give the length and width of another rectangular field that has the same perimeter but a larger area.width = yardslength = yards

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