To solve this problem, we need to use the formula for work done, which is force times distance. In this case, the force is the weight of the water and the distance is the height it needs to be pumped.

1. First, we need to calculate the volume of the water in the tank. Since the tank is a rectangular prism, we can use the formula for the volume of a rectangular prism, which is length times width times height. In this case, a = 4 m, b = 4 m, and c = 6 m, so the volume V is 4m * 4m * 6m = 96 cubic meters.

2. Next, we need to calculate the weight of the water. The weight density of water is given as 1000 kg/m3, so the weight W of the water is the volume times the weight density, or 96 m3 * 1000 kg/m3 = 96000 kg.

3. The force required to lift this water is its weight times the acceleration due to gravity. Using g = 9.8 m/s2, the force F is 96000 kg * 9.8 m/s2 = 940800 N.

4. Finally, we need to calculate the work done to pump the water out of the spout. The work W is the force times the distance, where the distance d is the height the water needs to be pumped. In this case, d = 1 m, so the work W is 940800 N * 1 m = 940800 Joules.

So, the work required to pump the water out of the spout is 940800 Joules.

Question

To solve this problem, we need to use the formula for work done, which is force times distance. In this case, the force is the weight of the water and the distance is the height it needs to be pumped.

1. First, we need to calculate the volume of the water in the tank. Since the tank is a rectangular prism, we can use the formula for the volume of a rectangular prism, which is length times width times height. In this case, a = 4 m, b = 4 m, and c = 6 m, so the volume V is 4m * 4m * 6m = 96 cubic meters.

2. Next, we need to calculate the weight of the water. The weight density of water is given as 1000 kg/m3, so the weight W of the water is the volume times the weight density, or 96 m3 * 1000 kg/m3 = 96000 kg.

3. The force required to lift this water is its weight times the acceleration due to gravity. Using g = 9.8 m/s2, the force F is 96000 kg * 9.8 m/s2 = 940800 N.

4. Finally, we need to calculate the work done to pump the water out of the spout. The work W is the force times the distance, where the distance d is the height the water needs to be pumped. In this case, d = 1 m, so the work W is 940800 N * 1 m = 940800 Joules.

So, the work required to pump the water out of the spout is 940800 Joules.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for work done, which is force times distance. In this case, the force is the weight of the water and the distance is the height it needs to be pumped.

1. First, we need to calculate the volume of the water in the tank. Since the tank is a rectangular prism, we can use the formula for the volume of a rectangular prism, which is length times width times height. In this case, a = 4 m, b = 4 m, and c = 6 m, so the volume V is 4m * 4m * 6m = 96 cubic meters.

2. Next, we need to calculate the weight of the water. The weight density of water is given as 1000 kg/m3, so the weight W of the water is the volume times the weight density, or 96 m3 * 1000 kg/m3 = 96000 kg.

3. The force required to lift this water is its weight times the acceleration due to gravity. Using g = 9.8 m/s2, the force F is 96000 kg * 9.8 m/s2 = 940800 N.

4. Finally, we need to calculate the work done to pump the water out of the spout. The work W is the force times the distance, where the distance d is the height the water needs to be pumped. In this case, d = 1 m, so the work W is 940800 N * 1 m = 940800 Joules.

So, the work required to pump the water out of the spout is 940800 Joules.

A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the weight density of water. Assume that a = 4 m, b = 4 m, c = 6 m, and d = 1 m.)W

Question

Solution

Similar Questions

Upgrade your grade with Knowee