int crypto(int num) { if (num % 2 == 0) return num / 2; else if (num % 2 != 0) return num - 1;}int currency(int num) { int bit = 0; while (num > 0) { num = crypto(num) bit += 1; } return bit;}
Question
int crypto(int num) { if (num % 2 == 0) return num / 2; else if (num % 2 != 0) return num - 1;}int currency(int num) { int bit = 0; while (num > 0) { num = crypto(num) bit += 1; } return bit;}
Solution
The provided code is written in C or C++ language. It consists of two functions: crypto and currency.
The crypto function takes an integer num as an input. If num is even, it returns num / 2. If num is odd, it returns num - 1.
The currency function also takes an integer num as an input. It initializes a variable bit to 0. Then it enters a while loop which continues as long as num is greater than 0. Inside the loop, num is updated by calling the crypto function with num as the argument, and bit is incremented by 1. Finally, the function returns bit.
However, there is a syntax error in the currency function. After calling the crypto function, there should be a semicolon (;). The corrected code is:
int crypto(int num) {
if (num % 2 == 0)
return num / 2;
else if (num % 2 != 0)
return num - 1;
}
int currency(int num) {
int bit = 0;
while (num > 0) {
num = crypto(num);
bit += 1;
}
return bit;
}
This corrected currency function will now correctly calculate and return the number of times the crypto function needs to be applied to num to reduce it to 0.
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