In a perfectly inelastic collision, the two bodies stick together and move as one after the collision. The law of conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision.

The total momentum before the collision is the sum of the momenta of the two bodies. Momentum is calculated as the product of mass and velocity.

For the 4 kg body:
Momentum = mass * velocity = 4 kg * 3 m/s = 12 kg*m/s

For the 2 kg body moving in the opposite direction, its velocity is considered negative:
Momentum = mass * velocity = 2 kg * -2 m/s = -4 kg*m/s

The total initial momentum is: 12 kg*m/s - 4 kg*m/s = 8 kg*m/s

After the collision, the two bodies move together with a combined mass of 4 kg + 2 kg = 6 kg.

Let's denote their common velocity as v. According to the law of conservation of momentum, the total momentum after the collision is also 8 kg*m/s.

So, we can set up the equation:
6 kg * v = 8 kg*m/s

Solving for v gives:
v = 8 kg*m/s / 6 kg = 1.33 m/s

So, the velocity of the two bodies after the collision is 1.33 m/s.

Question

In a perfectly inelastic collision, the two bodies stick together and move as one after the collision. The law of conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision.

The total momentum before the collision is the sum of the momenta of the two bodies. Momentum is calculated as the product of mass and velocity.

For the 4 kg body: 
Momentum = mass * velocity = 4 kg * 3 m/s = 12 kg*m/s

For the 2 kg body moving in the opposite direction, its velocity is considered negative: 
Momentum = mass * velocity = 2 kg * -2 m/s = -4 kg*m/s

The total initial momentum is: 12 kg*m/s - 4 kg*m/s = 8 kg*m/s

After the collision, the two bodies move together with a combined mass of 4 kg + 2 kg = 6 kg.

Let's denote their common velocity as v. According to the law of conservation of momentum, the total momentum after the collision is also 8 kg*m/s.

So, we can set up the equation: 
6 kg * v = 8 kg*m/s

Solving for v gives: 
v = 8 kg*m/s / 6 kg = 1.33 m/s

So, the velocity of the two bodies after the collision is 1.33 m/s.

Knowee AI · Accepted Answer

In a perfectly inelastic collision, the two bodies stick together and move as one after the collision. The law of conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision.

The total momentum before the collision is the sum of the momenta of the two bodies. Momentum is calculated as the product of mass and velocity.

For the 4 kg body: 
Momentum = mass * velocity = 4 kg * 3 m/s = 12 kg*m/s

For the 2 kg body moving in the opposite direction, its velocity is considered negative: 
Momentum = mass * velocity = 2 kg * -2 m/s = -4 kg*m/s

The total initial momentum is: 12 kg*m/s - 4 kg*m/s = 8 kg*m/s

After the collision, the two bodies move together with a combined mass of 4 kg + 2 kg = 6 kg.

Let's denote their common velocity as v. According to the law of conservation of momentum, the total momentum after the collision is also 8 kg*m/s.

So, we can set up the equation: 
6 kg * v = 8 kg*m/s

Solving for v gives: 
v = 8 kg*m/s / 6 kg = 1.33 m/s

So, the velocity of the two bodies after the collision is 1.33 m/s.

A body of mass 4 kg moving at a speed of 3 m/s collides with another body of mass 2 kg moving at 2 m/s in the opposite direction. If the collision is perfectly inelastic, find the velocity of the two bodies after the collision.*1 point1.33 m/s2.34 m/s3.22 m/s4.00 m/s

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