Chemistry I16) A 0.10-L container holds 3.0 x 10^20 molecules of H2 at 100 kPa and 0C. If the volume of a hydrogen molecule is 6.7 x 10^-24 mL, what percentage of the volume of the gas is occupied by its molecules? 3.0 x 10^-1 % 2.0 x 10^-3 % 3.0 x 10^-3 % 2.0 x 10^-1 %Previous Question Next QuestionDo not use the 'Forward' or 'Back' button on your browser.
Question
Chemistry I16) A 0.10-L container holds 3.0 x 10^20 molecules of H2 at 100 kPa and 0C. If the volume of a hydrogen molecule is 6.7 x 10^-24 mL, what percentage of the volume of the gas is occupied by its molecules? 3.0 x 10^-1 % 2.0 x 10^-3 % 3.0 x 10^-3 % 2.0 x 10^-1 %Previous Question Next QuestionDo not use the 'Forward' or 'Back' button on your browser.
Solution
First, we need to calculate the total volume of the hydrogen molecules.
The volume of one molecule of hydrogen is given as 6.7 x 10^-24 mL.
So, the total volume of 3.0 x 10^20 molecules of hydrogen is:
(6.7 x 10^-24 mL/molecule) x (3.0 x 10^20 molecules) = 2.01 x 10^-3 mL
Next, we need to convert the volume of the container from liters to milliliters, since the volume of the molecules is given in milliliters.
1 L = 1000 mL, so 0.10 L = 100 mL
Finally, we can calculate the percentage of the volume of the gas that is occupied by its molecules:
(2.01 x 10^-3 mL / 100 mL) x 100% = 2.01 x 10^-2 %
So, none of the given options are correct. The percentage of the volume of the gas that is occupied by its molecules is 2.01 x 10^-2 %.
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