The error in the given Java code is due to the fact that the multiplication operation is converting the result into an integer. In Java, when two bytes are multiplied, the result is an integer. Therefore, `b * 50` results in an integer.

However, the variable `b` is declared as a byte. In Java, a byte has a maximum value of 127, and an integer is larger than a byte. Therefore, you cannot store an integer value in a byte without explicit casting.

So, the correct code should be:

```java
byte b = 50;
b = (byte)(b * 50);
```

This code first multiplies `b` by 50, then explicitly casts the result to a byte before storing it back in `b`.

Question

The error in the given Java code is due to the fact that the multiplication operation is converting the result into an integer. In Java, when two bytes are multiplied, the result is an integer. Therefore, `b * 50` results in an integer.

However, the variable `b` is declared as a byte. In Java, a byte has a maximum value of 127, and an integer is larger than a byte. Therefore, you cannot store an integer value in a byte without explicit casting.

So, the correct code should be:

```java
byte b = 50;
b = (byte)(b * 50);
```

This code first multiplies `b` by 50, then explicitly casts the result to a byte before storing it back in `b`.

Knowee AI · Accepted Answer

The error in the given Java code is due to the fact that the multiplication operation is converting the result into an integer. In Java, when two bytes are multiplied, the result is an integer. Therefore, `b * 50` results in an integer.

However, the variable `b` is declared as a byte. In Java, a byte has a maximum value of 127, and an integer is larger than a byte. Therefore, you cannot store an integer value in a byte without explicit casting.

So, the correct code should be:

```java
byte b = 50;
b = (byte)(b * 50);
```

This code first multiplies `b` by 50, then explicitly casts the result to a byte before storing it back in `b`.

What will be the error in the following Java code?byte b = 50;b = b * 50;b cannot contain value 50b cannot contain value 100, limited by its rangeNo error in this code* operator has converted b * 50 into int, which can not be converted to byte without casting

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