What is the maximum number of comparisons required to find an element in a sorted array of size 31 using Binary Search?4567
Question
What is the maximum number of comparisons required to find an element in a sorted array of size 31 using Binary Search?4567
Solution
The maximum number of comparisons required to find an element in a sorted array of size 31 using Binary Search can be calculated using the formula log2(n) + 1, where n is the size of the array.
Step 1: Calculate log2(31) which is approximately 4.95.
Step 2: Add 1 to the result from step 1. So, 4.95 + 1 = 5.95.
Since we can't have a fraction of a comparison, we round up to the nearest whole number.
So, the maximum number of comparisons required is 6.
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