In one experimental trial, the projectile was uniformly accelerated from rest to a distance of 2 m in 0.1 s. What was the acceleration of the projectile?A.20 m/s2B.40 m/s2C.200 m/s2D.400 m/s2
Question
In one experimental trial, the projectile was uniformly accelerated from rest to a distance of 2 m in 0.1 s. What was the acceleration of the projectile?A.20 m/s2B.40 m/s2C.200 m/s2D.400 m/s2
Solution
To solve this problem, we can use the formula for acceleration which is:
a = 2*(d - v0*t) / t^2
where:
- a is acceleration
- d is distance
- v0 is initial velocity
- t is time
Given in the problem, the projectile was accelerated from rest, so the initial velocity (v0) is 0. The distance (d) is 2 m and the time (t) is 0.1 s.
Substituting these values into the formula, we get:
a = 2*(2 - 00.1) / 0.1^2 a = 22 / 0.01 a = 400 m/s^2
So, the acceleration of the projectile was 400 m/s^2. Therefore, the correct answer is D.400 m/s^2.
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