Let's denote the time it takes for the smaller pipe to fill the tank as x (in minutes). According to the problem, the larger pipe takes 5 minutes less to fill the tank, so we can denote its time as x - 5.

The rate of work done is the reciprocal of the time taken to complete the work. So, the rate of work done by the smaller pipe is 1/x and the rate of work done by the larger pipe is 1/(x - 5).

When the two pipes are opened together, they can fill the tank in 11 19/60 minutes (or approximately 11.3167 minutes). So, their combined rate of work is 1/(11 19/60) or approximately 0.0883 tanks per minute.

According to the problem, the sum of the rates of the two pipes working together equals the combined rate. So, we can set up the following equation:

1/x + 1/(x - 5) = 0.0883

To solve this equation for x, you might find it easier to first clear the fractions by multiplying every term by x(x - 5):

x + x - 5 = 0.0883 * x(x - 5)

Solving this equation will give you the time it takes for the smaller pipe to fill the tank. Subtracting 5 from this result will give you the time for the larger pipe.

Question

Let's denote the time it takes for the smaller pipe to fill the tank as x (in minutes). According to the problem, the larger pipe takes 5 minutes less to fill the tank, so we can denote its time as x - 5.

The rate of work done is the reciprocal of the time taken to complete the work. So, the rate of work done by the smaller pipe is 1/x and the rate of work done by the larger pipe is 1/(x - 5).

When the two pipes are opened together, they can fill the tank in 11 19/60 minutes (or approximately 11.3167 minutes). So, their combined rate of work is 1/(11 19/60) or approximately 0.0883 tanks per minute.

According to the problem, the sum of the rates of the two pipes working together equals the combined rate. So, we can set up the following equation:

1/x + 1/(x - 5) = 0.0883

To solve this equation for x, you might find it easier to first clear the fractions by multiplying every term by x(x - 5):

x + x - 5 = 0.0883 * x(x - 5)

Solving this equation will give you the time it takes for the smaller pipe to fill the tank. Subtracting 5 from this result will give you the time for the larger pipe.

Knowee AI · Accepted Answer

Let's denote the time it takes for the smaller pipe to fill the tank as x (in minutes). According to the problem, the larger pipe takes 5 minutes less to fill the tank, so we can denote its time as x - 5.

The rate of work done is the reciprocal of the time taken to complete the work. So, the rate of work done by the smaller pipe is 1/x and the rate of work done by the larger pipe is 1/(x - 5).

When the two pipes are opened together, they can fill the tank in 11 19/60 minutes (or approximately 11.3167 minutes). So, their combined rate of work is 1/(11 19/60) or approximately 0.0883 tanks per minute.

According to the problem, the sum of the rates of the two pipes working together equals the combined rate. So, we can set up the following equation:

1/x + 1/(x - 5) = 0.0883

To solve this equation for x, you might find it easier to first clear the fractions by multiplying every term by x(x - 5):

x + x - 5 = 0.0883 * x(x - 5)

Solving this equation will give you the time it takes for the smaller pipe to fill the tank. Subtracting 5 from this result will give you the time for the larger pipe.

A tank can be ﬁlled with water by two pipes running together in 11 19 minutes. If thelarger pipe alone takes 5 minutes less to ﬁll the tank than the smaller pipe, ﬁnd the timethat each pipe will take to ﬁll the tank.

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