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It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.InputThe single line contains integer y (1000 ≤ y ≤ 9000) — the year number.OutputPrint a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Question

It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.InputThe single line contains integer y (1000 ≤ y ≤ 9000) — the year number.OutputPrint a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

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Solution

To solve this problem, you can follow these steps:

  1. Increment the given year by 1 to find the next year.
  2. Convert the year to a string to easily access each digit.
  3. Check if all the digits in the year are distinct. You can do this by converting the string to a set and comparing the lengths. If all digits are distinct, the length of the set will be equal to the length of the string.
  4. If the year does not have distinct digits, go back to step 1.
  5. Once you find a year with distinct digits, return that year.

Here is a Python solution following these steps:

def find_next_distinct_year(year):
    while True:
        year += 1
        if len(set(str(year))) == len(str(year)):
            return year

You can call this function with the given year to find the next year with distinct digits. For example:

print(find_next_distinct_year(1987))  # Output: 2013

This function works by continuously incrementing the year until it finds a year with distinct digits. It checks for distinct digits by converting the year to a string and then to a set. Since sets only contain unique elements, if the length of the set is equal to the length of the string, that means all digits are distinct.

This problem has been solved

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