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n a certain application, a Half wave controlled rectifier is fed from a voltage vs(t)=320sin(100pi (t)) as shown in figure with an inductive load and a free-wheeling diode. The thyristor firing angle is 90 degrees. Therefore the average output voltage in Volts across the load is: Select one:a. 50.93b. 88.86c. 106.67d. 41.12

Question

n a certain application, a Half wave controlled rectifier is fed from a voltage vs(t)=320sin(100pi (t)) as shown in figure with an inductive load and a free-wheeling diode. The thyristor firing angle is 90 degrees. Therefore the average output voltage in Volts across the load is: Select one:a. 50.93b. 88.86c. 106.67d. 41.12

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Solution

The average output voltage (Vavg) for a half-wave controlled rectifier with a firing angle (α) can be calculated using the following formula:

Vavg = (2Vm/π) * (1 + cosα)

Where:

  • Vm is the peak voltage, which is 320V in this case.
  • α is the firing angle, which is 90 degrees in this case.

Substituting the given values into the formula, we get:

Vavg = (2*320/π) * (1 + cos90) = (640/π) * (1 + 0) = 640/π = 203.64V

However, since it's a half-wave rectifier, we only get the output for half the input cycle. So, we divide the result by 2:

Vavg = 203.64/2 = 101.82V

This value is not listed in the options provided. There might be a mistake in the question or the options provided. Please check the values again.

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