An engineering school reports that 55% of its students were male (M), 40% of its students were between the ages of 18 and 20 (A), and that 25% were both male and between the ages of 18 and 20.What is the probability of a random student being female between the ages of 18 and 20? Assume P(F) = P(not M). 0.15 0.16 0.30 0.40

The CSU system reported the following probabilities for their student body in 2013. The probability of their student being a male between 17 and 19 is P(A) = 0.11. The probability of their student being a female between 20 and 24, P(B) = 0.30. What is P(A and B) given that year? 0.033 0.410 0.377 0

In a certain liberal arts college with about 10,000 students, 40% are males. If two students from this college are selected at random, what is the probability that they are of the same gender? 0.96 0.52 0.48 0.36 0.16

In a class of 30 students, 20 are female and 5 have an A in the class. There are 3 students who are female and have an A in the class. What is the probability that a student chosen randomly from the class is a female?

A test was given to a group of students. The grades and gender are summarized belowA B C TotalMale 8 18 17 43Female 15 5 10 30Total 23 23 27 73If one student is chosen at random from those who took the test,Find the probability that the student was female GIVEN they got an 'A'.

Here is a table of the education level and the sex for our sample: counts Female (F) Male (M) Total High School (HS) 124 117 241 Less than High School (LHS) 136 105 241 More than High School (MHS) 215 177 392 Total 475 400 875 Calculate the probability P(HS and F). Represent your answer as a fraction. Calculate the probability P(F | MHS). Represent your answer as a fraction. Calculate the probability P(F or LHS). Represent your answer as a fraction. Between which group, Male or Female, is the likelihood of having a high school education the highest? Explain, using the appropriate fractions and notation.