Calculate power if a pump which can lift 400kg of water through a height of 10m in 20secs?

An electric pump is used to raise water from a well, as shown.The pump does work in raising 10 kg of the water through a vertical distance of 8.0 m in 5.0 s. Calculate the power the pump uses to raise the water.

The volumetric flow rate to be pumped is 4 L/s.The required useful pump head = 131 m The efficiency of the pump is to be 79 %.The density and viscosity of water at anticipated operation conditions are taken to be 1000 kg/m3 and 0.00131 kg/m-s, respectively.Determine the power requirement of the pump in kW.

A water pump is pumping up water from a well which is 120 m deep.How much work must be done by the pump to raise 2 kg of water?(g=9.8 m s^-2)

Water is to be pumped through a vertical height difference of 12.5 m. The pump is driven by a wind turbine that has an efficiency of 50 % and an area swept by the blades of 100 m2. The average wind speed is 5.0 m s−1 and the air density is 1.2 kg m−3.What is the maximum mass of water that can be pumped every second?A.  3 kgB.  30 kgC.  60 kgD.  120 kg

The input power of an electric motor is 200W. It is used to raise a mass of 10kg at constant speed.If the efficiency of the motor is 40%, through what height will the mass be raised in 1 second?A. 0.5mB. 0.8mC. 1.2mD. 2.0m