Kishang Ojha is walking on the x-axis.  He starts from x = 7 m and walks 8 m in the positive direction.  Then he stops, turns back and walks 20 m in the negative direction and again turns around and finally walks 9 m in the positive direction.  He does all this in a total time of 20 seconds. You can say that: We can only find Kishang’s average velocity, not his average speed.We can only find Kishang’s average speed, not his average velocity.Kishang’s average speed = 2.2 m/sKishang’s average velocity = -0.15 m/s

To answer this question, we first need to understand the concepts of average speed and average velocity.

1. Average Speed: This is the total distance traveled divided by the total time taken. It does not take into account the direction of the movement.

2. Average Velocity: This is the total displacement (change in position) divided by the total time taken. It does take into account the direction of the movement.

Now, let's calculate both for Kishang Ojha:

1. Total Distance Travelled: He walks 8m in the positive direction, 20m in the negative direction, and finally 9m in the positive direction. So, the total distance he travelled is 8m + 20m + 9m = 37m.

2. Total Displacement: He starts from x = 7m, walks 8m in the positive direction (reaching x = 15m), then 20m in the negative direction (reaching x = -5m), and finally 9m in the positive direction (ending at x = 4m). So, his total displacement is 4m - 7m = -3m.

3. Total Time: This is given as 20 seconds.

Now we can calculate his average speed and average velocity:

1. Average Speed = Total Distance / Total Time = 37m / 20s = 1.85 m/s
2. Average Velocity = Total Displacement / Total Time = -3m / 20s = -0.15 m/s

So, the correct answer is: "Kishang’s average speed = 1.85 m/s, Kishang’s average velocity = -0.15 m/s".