The acceleration of a body falling near the surface of a planet is given by the formula:

g = GM/r^2

where:
- G is the gravitational constant,
- M is the mass of the planet, and
- r is the radius of the planet.

Given that Venus has a mass of about 0.0558 times the mass of Earth and a diameter of about 0.381 times the diameter of Earth, we can substitute these values into the formula.

However, we need to remember that the mass of Earth is about 5.972 × 10^24 kg, the gravitational constant G is about 6.674 × 10^-11 N(m/kg)^2, and the radius of Earth is about 6.371 × 10^6 m.

So, the mass of Venus is about 0.0558 * 5.972 × 10^24 kg = 3.33 × 10^23 kg, and the radius of Venus is about 0.381/2 * 6.371 × 10^6 m = 1.21 × 10^6 m.

Substituting these values into the formula gives:

g = (6.674 × 10^-11 N(m/kg)^2 * 3.33 × 10^23 kg) / (1.21 × 10^6 m)^2
g = 8.8 m/s^2

So, the acceleration of a body falling near the surface of Venus is about 8.8 m/s^2. However, this value is not in the provided answer choices. Please check the question or the provided data again.

Question

The acceleration of a body falling near the surface of a planet is given by the formula:

g = GM/r^2

where:
- G is the gravitational constant,
- M is the mass of the planet, and
- r is the radius of the planet.

Given that Venus has a mass of about 0.0558 times the mass of Earth and a diameter of about 0.381 times the diameter of Earth, we can substitute these values into the formula.

However, we need to remember that the mass of Earth is about 5.972 × 10^24 kg, the gravitational constant G is about 6.674 × 10^-11 N(m/kg)^2, and the radius of Earth is about 6.371 × 10^6 m.

So, the mass of Venus is about 0.0558 * 5.972 × 10^24 kg = 3.33 × 10^23 kg, and the radius of Venus is about 0.381/2 * 6.371 × 10^6 m = 1.21 × 10^6 m.

Substituting these values into the formula gives:

g = (6.674 × 10^-11 N(m/kg)^2 * 3.33 × 10^23 kg) / (1.21 × 10^6 m)^2
g = 8.8 m/s^2

So, the acceleration of a body falling near the surface of Venus is about 8.8 m/s^2. However, this value is not in the provided answer choices. Please check the question or the provided data again.

Knowee AI · Accepted Answer

The acceleration of a body falling near the surface of a planet is given by the formula:

g = GM/r^2

where:
- G is the gravitational constant,
- M is the mass of the planet, and
- r is the radius of the planet.

Given that Venus has a mass of about 0.0558 times the mass of Earth and a diameter of about 0.381 times the diameter of Earth, we can substitute these values into the formula.

However, we need to remember that the mass of Earth is about 5.972 × 10^24 kg, the gravitational constant G is about 6.674 × 10^-11 N(m/kg)^2, and the radius of Earth is about 6.371 × 10^6 m.

So, the mass of Venus is about 0.0558 * 5.972 × 10^24 kg = 3.33 × 10^23 kg, and the radius of Venus is about 0.381/2 * 6.371 × 10^6 m = 1.21 × 10^6 m.

Substituting these values into the formula gives:

g = (6.674 × 10^-11 N(m/kg)^2 * 3.33 × 10^23 kg) / (1.21 × 10^6 m)^2
g = 8.8 m/s^2

So, the acceleration of a body falling near the surface of Venus is about 8.8 m/s^2. However, this value is not in the provided answer choices. Please check the question or the provided data again.

Venus has a mass of about 0.0558 times the mass of Earth and a diameter of about 0.381 times the diameter of Earth. The acceleration of a body (in m/s2) falling near the surface of Venus is about:Group of answer choices251.43.80.212.8

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