The areas of two similar triangles are 81 cm2 and 49 cm2 respectively, then the ratio of their corresponding medians is
Question
The areas of two similar triangles are 81 cm2 and 49 cm2 respectively, then the ratio of their corresponding medians is
Solution
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding lengths (including medians).
Given that the areas of the two triangles are 81 cm² and 49 cm², we can find the ratio of the areas by dividing the larger area by the smaller area:
81 cm² / 49 cm² = 1.65306122449
Since the ratio of the areas is equal to the square of the ratio of the corresponding lengths, we can find the ratio of the corresponding lengths (medians) by taking the square root of the ratio of the areas:
sqrt(1.65306122449) = 1.28571428571
Therefore, the ratio of the corresponding medians of the two triangles is approximately 1.29:1.
Similar Questions
The areas of two similar triangles are 100 cm2 and 64 cm2, respectively. If the median of the bigger triangle is 5 cm, then the corresponding median of the smaller triangle is:
The areas of two similar figures are in a ratio of 49 :16. What is the ratio of their sides?Question 7
Medians of a triangle cut each other in the ratio
he perimeters of two similar triangles are 26 cm and 39 cm. The ratio of their areas will be
Given two similar triangles ABC and PQR. If their corresponding altitudes AD and PS are in the ratio 5 : 11, then the ratio of the areas of ABC and PQR is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.