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The areas of two similar triangles are 81 cm2 and 49 cm2 respectively, then the ratio of their corresponding medians is

Question

The areas of two similar triangles are 81 cm2 and 49 cm2 respectively, then the ratio of their corresponding medians is

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Solution

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding lengths (including medians).

Given that the areas of the two triangles are 81 cm² and 49 cm², we can find the ratio of the areas by dividing the larger area by the smaller area:

81 cm² / 49 cm² = 1.65306122449

Since the ratio of the areas is equal to the square of the ratio of the corresponding lengths, we can find the ratio of the corresponding lengths (medians) by taking the square root of the ratio of the areas:

sqrt(1.65306122449) = 1.28571428571

Therefore, the ratio of the corresponding medians of the two triangles is approximately 1.29:1.

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