Two small balls having equal charges Q, are suspended from a hook with two insulating threads each of length L. This arrangement is carried in the space, where there is no gravitation. The tension in each string will be-

To find the tension in each string, we can use the concept of electrostatic forces. Since the two small balls have equal charges Q, they will repel each other due to the electrostatic force.

Step 1: Draw a diagram of the arrangement with the two small balls suspended from the hook with two insulating threads of length L.

Step 2: Identify the forces acting on each ball. In this case, there are two forces acting on each ball: the tension in the string and the electrostatic force due to the repulsion between the balls.

Step 3: Since the arrangement is in a space with no gravitation, we can neglect the weight of the balls.

Step 4: The tension in each string can be calculated by considering the equilibrium of forces. The tension in each string must balance the electrostatic force between the balls.

Step 5: The electrostatic force between the balls can be calculated using Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Step 6: Since the balls have equal charges Q, the electrostatic force between them can be written as F = k(Q^2)/L^2, where k is the electrostatic constant.

Step 7: The tension in each string must balance this electrostatic force. Therefore, the tension in each string will be equal to half of the electrostatic force, as the forces are equal and opposite.

Step 8: Therefore, the tension in each string can be calculated as T = (1/2)(k(Q^2)/L^2).

Step 9: Simplify the expression to get the final answer for the tension in each string.

Note: The specific value of the tension in each string will depend on the values of the charges Q and the length L, as well as the electrostatic constant k.